Problem 53
#include <stdio.h>
struct student_record {
char name[50];
char branch[50];
int total_marks;
};
int main() {
/*53. Design a structure student_record to contain name, branch and total marks obtained.
Develop a program to read data for 10 students in a class and print them.*/
struct student_record student[10];
int i;
printf("\tStudent Details\n");
printf("==========================================");
for (i = 0; i < 10; i++) {
printf("\n\nEnter Name For Student %d: ", i+1);
scanf("%s", student[i].name);
printf("\nEnter Branch For Student %d: ", i+1);
scanf("%s", student[i].branch);
printf("\nEnter Total Marks For Student %d: ", i+1);
scanf("%d", &student[i].total_marks);
}
printf("\nStudent Records:\n");
for (i = 0; i < 10; i++) {
printf("\nName: %s\n", student[i].name);
printf("Branch: %s\n", student[i].branch);
printf("Total Marks: %d\n", student[i].total_marks);
printf("\n");
}
return 0;
}
- This program is designed to read and display the data of 10 students using a structure called
student_record. - The program starts by defining the
student_recordstructure that contains three members -name,branch, andtotal_marks- to hold the information for each student. - In the
main()function, an array of 10student_recordstructures is declared. - The program then prompts the user to enter the details for each student using a
forloop. The details include the student's name, branch, and total marks. - The program reads the input values using
scanf()function and stores them in the corresponding member variables of thestudent_recordstructure. - After all the data has been read and stored in the array of structures, the program then prints the student details using another
forloop. - The program uses
printf()function to display the student's name, branch, and total marks in a formatted manner. - Finally, the program returns 0 to indicate successful completion.
